io: fix possible double free of task error object
If a QIOTask has an error set and the calling code uses qio_task_propagate_error() to steal the reference to that Error object, the task would not clear its own reference. This would lead to a double-free when qio_task_free runs, if the caller had (correctly) freed the Error object they now owned. Signed-off-by: Daniel P. Berrange <berrange@redhat.com>
This commit is contained in:
		
							parent
							
								
									c7f1cf01b8
								
							
						
					
					
						commit
						80fb34eda0
					
				| 
						 | 
				
			
			@ -157,6 +157,7 @@ bool qio_task_propagate_error(QIOTask *task,
 | 
			
		|||
{
 | 
			
		||||
    if (task->err) {
 | 
			
		||||
        error_propagate(errp, task->err);
 | 
			
		||||
        task->err = NULL;
 | 
			
		||||
        return true;
 | 
			
		||||
    }
 | 
			
		||||
 | 
			
		||||
| 
						 | 
				
			
			
 | 
			
		|||
| 
						 | 
				
			
			@ -127,7 +127,7 @@ static void test_task_failure(void)
 | 
			
		|||
    g_assert(data.source == obj);
 | 
			
		||||
    g_assert(data.err == err);
 | 
			
		||||
    g_assert(data.freed == false);
 | 
			
		||||
 | 
			
		||||
    error_free(data.err);
 | 
			
		||||
}
 | 
			
		||||
 | 
			
		||||
 | 
			
		||||
| 
						 | 
				
			
			@ -238,6 +238,8 @@ static void test_task_thread_failure(void)
 | 
			
		|||
    g_assert(data.source == obj);
 | 
			
		||||
    g_assert(data.err != NULL);
 | 
			
		||||
 | 
			
		||||
    error_free(data.err);
 | 
			
		||||
 | 
			
		||||
    self = g_thread_self();
 | 
			
		||||
 | 
			
		||||
    /* Make sure the test_task_thread_worker actually got
 | 
			
		||||
| 
						 | 
				
			
			
 | 
			
		|||
		Loading…
	
		Reference in New Issue